btt: Fix overlapping IO stats.
authorGwendal Grignou <gwendal@chromium.org>
Fri, 18 Aug 2017 22:00:22 +0000 (15:00 -0700)
committerJens Axboe <axboe@kernel.dk>
Tue, 7 Nov 2017 18:25:38 +0000 (11:25 -0700)
Keep scanning the tree for overlapping IO otherwise Q2G and process
traces will be incorrect.

Let assume we have 2 IOs:

A                                      A+a
|---------------------------------------|
       B                B+b
       |-----------------|

In the red/black tree we have:

                    o -> [A,A+a]
                   / \
                left right
                 /    \
           [...]o      o -> [B, B+b]

In the current code, if we would not be able to find [B+b] in the tree:
B is greater than A, so we won't go left
B+b is smaller than A+a, so we are not going right either.

When we have a [X, X+x] IO to look for:
We need to check for right when either:
 X+x >= A+a (for merged IO)
and
 X > A (for overlapping IO)

TEST=Check with a trace with overlapping IO: Q2C and Q2G are expected.

Signed-off-by: Gwendal Grignou <gwendal@chromium.org>
Signed-off-by: Jens Axboe <axboe@kernel.dk>
btt/dip_rb.c

index 2aa7ffcc763b01145b5b0b7f07c806c347eb8e3c..6efef6c03b8f599a89035c59b35fefd9b75da432 100644 (file)
@@ -57,7 +57,7 @@ struct io *rb_find_sec(struct rb_root *root, __u64 sec)
                __iop = rb_entry(n, struct io, rb_node);
                if (sec < BIT_START(__iop))
                        n = n->rb_left;
-               else if (sec >= BIT_END(__iop))
+               else if (sec > BIT_START(__iop))
                        n = n->rb_right;
                else
                        return __iop;
@@ -82,7 +82,7 @@ void rb_foreach(struct rb_node *n, struct io *iop,
                }
                if (iop_s < this_s)
                        rb_foreach(n->rb_left, iop, fnc, head);
-               if (this_e < iop_e)
+               if ((this_e < iop_e) || (this_s < iop_s))
                        rb_foreach(n->rb_right, iop, fnc, head);
        }
 }