- /* No right-hand children. Everything down and left is
- smaller than us, so any 'next' node must be in the general
- direction of our parent. Go up the tree; any time the
- ancestor is a right-hand child of its parent, keep going
- up. First time it's a left-hand child of its parent, said
- parent is our 'next' node. */
- while (node->rb_parent && node == node->rb_parent->rb_right)
- node = node->rb_parent;
-
- return node->rb_parent;
-}
-
-struct rb_node *rb_prev(struct rb_node *node)
-{
- /* If we have a left-hand child, go down and then right as far
- as we can. */
- if (node->rb_left) {
- node = node->rb_left;
- while (node->rb_right)
- node=node->rb_right;
- return node;
- }
-
- /* No left-hand children. Go up till we find an ancestor which
- is a right-hand child of its parent */
- while (node->rb_parent && node == node->rb_parent->rb_left)
- node = node->rb_parent;
-
- return node->rb_parent;
+ /*
+ * No right-hand children. Everything down and left is smaller than us,
+ * so any 'next' node must be in the general direction of our parent.
+ * Go up the tree; any time the ancestor is a right-hand child of its
+ * parent, keep going up. First time it's a left-hand child of its
+ * parent, said parent is our 'next' node.
+ */
+ while ((parent = rb_parent(node)) && node == parent->rb_right)
+ node = parent;
+
+ return parent;