One of the more common cases of allocation size calculations is finding the
size of a structure that has a zero-sized array at the end, along with
memory for some number of elements for that array. For example:
struct foo {
int stuff;
struct boo entry[];
};
instance = vzalloc(sizeof(struct foo) + count * sizeof(struct boo));
Instead of leaving these open-coded and prone to type mistakes, use the new
struct_size() helper:
instance = vzalloc(struct_size(instance, entry, count));
This code was detected with the help of Coccinelle.
Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com>
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
Cc: "H. Peter Anvin" <hpa@zytor.com>
Link: https://lkml.kernel.org/r/20190403184230.GA5295@embeddedor
* another range split. So add extra two slots here.
*/
nr_ranges += 2;
- cmem = vzalloc(sizeof(struct crash_mem) +
- sizeof(struct crash_mem_range) * nr_ranges);
+ cmem = vzalloc(struct_size(cmem, ranges, nr_ranges));
if (!cmem)
return NULL;