Calling synchronize_irq() right before free_irq() is quite useless. On one
hand the IRQ can easily fire again before free_irq() is entered, on the
other hand free_irq() itself calls synchronize_irq() internally (in a race
condition free way), before any state associated with the IRQ is freed.
Reported-by: Zeal Robot <zealci@zte.com.cn>
Signed-off-by: Minghao Chi <chi.minghao@zte.com.cn>
Tested-by: Gurucharan <gurucharanx.g@intel.com> (A Contingent worker at Intel)
Signed-off-by: Tony Nguyen <anthony.l.nguyen@intel.com>
i40e_flush(&pf->hw);
if (pf->flags & I40E_FLAG_MSIX_ENABLED && pf->msix_entries) {
- synchronize_irq(pf->msix_entries[0].vector);
free_irq(pf->msix_entries[0].vector, pf);
clear_bit(__I40E_MISC_IRQ_REQUESTED, pf->state);
}
irq_set_affinity_notifier(irq_num, NULL);
/* remove our suggested affinity mask for this IRQ */
irq_update_affinity_hint(irq_num, NULL);
- synchronize_irq(irq_num);
free_irq(irq_num, vsi->q_vectors[i]);
/* Tear down the interrupt queue link list