Currently, the codegen function might fail and return an error. But its
callers continue without checking its return value. Since codegen can
fail only in the unlikely case of the system running out of memory or
the static template being malformed, just exit(-1) directly from codegen
and make it void-returning.
Suggested-by: Andrii Nakryiko <andrii.nakryiko@gmail.com>
Signed-off-by: Tobias Klauser <tklauser@distanz.ch>
Signed-off-by: Daniel Borkmann <daniel@iogearbox.net>
Acked-by: Andrii Nakryiko <andriin@fb.com>
Link: https://lore.kernel.org/bpf/20200611103341.21532-1-tklauser@distanz.ch
return err;
}
-static int codegen(const char *template, ...)
+static void codegen(const char *template, ...)
{
const char *src, *end;
int skip_tabs = 0, n;
n = strlen(template);
s = malloc(n + 1);
if (!s)
- return -ENOMEM;
+ exit(-1);
src = template;
dst = s;
p_err("unrecognized character at pos %td in template '%s'",
src - template - 1, template);
free(s);
- return -EINVAL;
+ exit(-1);
}
}
p_err("not enough tabs at pos %td in template '%s'",
src - template - 1, template);
free(s);
- return -EINVAL;
+ exit(-1);
}
}
/* trim trailing whitespace */
va_end(args);
free(s);
- return n;
+ if (n)
+ exit(-1);
}
static int do_skeleton(int argc, char **argv)