return -1;
}
+/*
+ * This function calculates the size of the larger block usable to map the
+ * beginning of an area based on the start address and size of that area:
+ * - max block size is 8M on 601 and 256 on other 6xx.
+ * - base address must be aligned to the block size. So the maximum block size
+ * is identified by the lowest bit set to 1 in the base address (for instance
+ * if base is 0x16000000, max size is 0x02000000).
+ * - block size has to be a power of two. This is calculated by finding the
+ * highest bit set to 1.
+ */
static unsigned int block_size(unsigned long base, unsigned long top)
{
unsigned int max_size = (cpu_has_feature(CPU_FTR_601) ? 8 : 256) << 20;
- unsigned int base_shift = (fls(base) - 1) & 31;
+ unsigned int base_shift = (ffs(base) - 1) & 31;
unsigned int block_shift = (fls(top - base) - 1) & 31;
return min3(max_size, 1U << base_shift, 1U << block_shift);
unsigned long __init mmu_mapin_ram(unsigned long base, unsigned long top)
{
- int done;
+ unsigned long done;
unsigned long border = (unsigned long)__init_begin - PAGE_OFFSET;
if (__map_without_bats) {
return __mmu_mapin_ram(base, top);
done = __mmu_mapin_ram(base, border);
- if (done != border - base)
+ if (done != border)
return done;
- return done + __mmu_mapin_ram(border, top);
+ return __mmu_mapin_ram(border, top);
}
void mmu_mark_initmem_nx(void)
*/
if ( ppc_md.progress ) ppc_md.progress("hash:find piece", 0x322);
Hash = memblock_alloc(Hash_size, Hash_size);
+ if (!Hash)
+ panic("%s: Failed to allocate %lu bytes align=0x%lx\n",
+ __func__, Hash_size, Hash_size);
_SDR1 = __pa(Hash) | SDR1_LOW_BITS;
Hash_end = (struct hash_pte *) ((unsigned long)Hash + Hash_size);